spoj#PDECODE. Decode the Strings
Decode the Strings
Bruce Force has had an interesting idea how to encode strings. The following is the description of how the encoding is done:
Let x1,x2,...,xn be the sequence of characters of the string to be encoded.
- Choose an integer m and n pairwise distinct numbers p1,p2,...,pn from the set {1, 2, ..., n} (a permutation of the numbers 1 to n).
- Repeat the following step m times.
- For 1 ≤ i ≤ n set yi to xpi, and then for 1 ≤ i ≤ n replace xi by yi.
For example, when we want to encode the string "hello", and we choose the value m = 3 and the permutation 2, 3, 1, 5, 4, the data would be encoded in 3 steps: "hello" -> "elhol" -> "lhelo" -> "helol".
Bruce gives you the encoded strings, and the numbers m and p1, ..., pn used to encode these strings. He claims that because he used huge numbers m for encoding, you will need a lot of time to decode the strings. Can you disprove this claim by quickly decoding the strings?
Input
The input contains several test cases. Each test case starts with a line containing two numbers n and m (1 ≤ n ≤ 80, 1 ≤ m ≤ 109). The following line consists of n pairwise different numbers p1,...,pn (1 ≤ pi ≤ n). The third line of each test case consists of exactly n characters, and represent the encoded string. The last test case is followed by a line containing two zeros.
Output
For each test case, print one line with the decoded string.
Example
Input: 5 3 2 3 1 5 4 helol 16 804289384 13 10 2 7 8 1 16 12 15 6 5 14 3 4 11 9 scssoet tcaede n 8 12 5 3 4 2 1 8 6 7 encoded? 0 0 Output: hello second test case encoded?