This is an interactive problem.

Homer likes arrays a lot and he wants to play a game with you.

Homer has hidden from you a permutation $a_1, a_2, \dots, a_n$ of integers $1$ to $n$. You are asked to find any index $k$ ($1 \leq k \leq n$) which is a local minimum.

For an array $a_1, a_2, \dots, a_n$, an index $i$ ($1 \leq i \leq n$) is said to be a local minimum if $a_i < \min\{a_{i-1},a_{i+1}\}$, where $a_0 = a_{n+1} = +\infty$. An array is said to be a permutation of integers $1$ to $n$, if it contains all integers from $1$ to $n$ exactly once.

Initially, you are only given the value of $n$ without any other information about this permutation.

At each interactive step, you are allowed to choose any $i$ ($1 \leq i \leq n$) and make a query with it. As a response, you will be given the value of $a_i$.

You are asked to find any index $k$ which is a local minimum after at most $100$ queries.

Interaction

You begin the interaction by reading an integer $n$ ($1\le n \le 10^5$) on a separate line.

To make a query on index $i$ ($1 \leq i \leq n$), you should output "? $i$" in a separate line. Then read the value of $a_i$ in a separate line. The number of the "?" queries is limited within $100$.

When you find an index $k$ ($1 \leq k \leq n$) which is a local minimum, output "! $k$" in a separate line and terminate your program.

In case your query format is invalid, or you have made more than $100$ "?" queries, you will receive Wrong Answer verdict.

After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:

• fflush(stdout) or cout.flush() in C++;
• System.out.flush() in Java;
• flush(output) in Pascal;
• stdout.flush() in Python;
• see documentation for other languages.

Hack Format

The first line of the hack should contain a single integer $n$ ($1 \leq n \leq 10^5$).

The second line should contain $n$ distinct integers $a_1, a_2, \dots, a_n$ ($1 \leq a_i \leq n$).