Score : $200$ points

Problem Statement

Takahashi loves numbers divisible by $2$.

You are given a positive integer $N$. Among the integers between $1$ and $N$ (inclusive), find the one that can be divisible by $2$ for the most number of times. The solution is always unique.

Here, the number of times an integer can be divisible by $2$, is how many times the integer can be divided by $2$ without remainder.

For example,

• $6$ can be divided by $2$ once: $6$ -> $3$.
• $8$ can be divided by $2$ three times: $8$ -> $4$ -> $2$ -> $1$.
• $3$ can be divided by $2$ zero times.

Constraints

• $1 \leq N \leq 100$

Input

Input is given from Standard Input in the following format:

$N$

Output

Print the answer.

7

4

$4$ can be divided by $2$ twice, which is the most number of times among $1$, $2$, ..., $7$.

32

32

1

1

100

64