这么简单的题目，何必写那么复杂呢？

#include <iostream>
using namespace std;
bool zhi(int a){
	if(a<=1)return false;
	for(int i=2;i*i<=a;i++)if(a%i==0)return false;
	return true;
}
int main(){
	int n;
	cin>>n;
	if(n==0)return 0;
	for(int i=1;i*2<=n;i++)if(zhi(i)&&zhi(n-i)){cout<<n<<" = "<<i<<" + "<<n-i<<endl;break;}
	return main();
}