10 条题解

  • -5
    @ 2022-1-22 22:11:04
    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    struct zzz {
        int t, nex;
    }e[500010 << 1]; int head[500010], tot;
    void add(int x, int y) {
    	e[++tot].t = y;
    	e[tot].nex = head[x];
    	head[x] = tot;
    }
    int depth[500001], fa[500001][22], lg[500001];
    void dfs(int now, int fath) {
    	fa[now][0] = fath; depth[now] = depth[fath] + 1;
    	for(int i = 1; i <= lg[depth[now]]; ++i)
    		fa[now][i] = fa[fa[now][i-1]][i-1];
    	for(int i = head[now]; i; i = e[i].nex)
    		if(e[i].t != fath) dfs(e[i].t, now);
    }
    int LCA(int x, int y) {
    	if(depth[x] < depth[y]) swap(x, y);
    	while(depth[x] > depth[y])
    		x = fa[x][lg[depth[x]-depth[y]] - 1];
    	if(x == y) return x;
    	for(int k = lg[depth[x]] - 1; k >= 0; --k)
    		if(fa[x][k] != fa[y][k])
    			x = fa[x][k], y = fa[y][k];
    	return fa[x][0];
    }
    int main() {
    	int n, m, s = 1; scanf("%d%d", &n, &m);
    	for(int i = 1; i <= n-1; ++i) {
    		int x, y; scanf("%d%d", &x, &y);
    		add(x, y); add(y, x);
    	}
    	for(int i = 1; i <= n; ++i)
    		lg[i] = lg[i-1] + (1 << lg[i-1] == i);
    	dfs(s, 0);
    	for(int i = 1; i <= m; ++i) {
    		int x, y; scanf("%d%d",&x, &y);
    		printf("%d\n", LCA(x, y));
    	}
    	return 0;
    }
    

    信息

    ID
    121
    时间
    2000ms
    内存
    256MiB
    难度
    6
    标签
    递交数
    667
    已通过
    194
    上传者