10 条题解
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-5
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; struct zzz { int t, nex; }e[500010 << 1]; int head[500010], tot; void add(int x, int y) { e[++tot].t = y; e[tot].nex = head[x]; head[x] = tot; } int depth[500001], fa[500001][22], lg[500001]; void dfs(int now, int fath) { fa[now][0] = fath; depth[now] = depth[fath] + 1; for(int i = 1; i <= lg[depth[now]]; ++i) fa[now][i] = fa[fa[now][i-1]][i-1]; for(int i = head[now]; i; i = e[i].nex) if(e[i].t != fath) dfs(e[i].t, now); } int LCA(int x, int y) { if(depth[x] < depth[y]) swap(x, y); while(depth[x] > depth[y]) x = fa[x][lg[depth[x]-depth[y]] - 1]; if(x == y) return x; for(int k = lg[depth[x]] - 1; k >= 0; --k) if(fa[x][k] != fa[y][k]) x = fa[x][k], y = fa[y][k]; return fa[x][0]; } int main() { int n, m, s = 1; scanf("%d%d", &n, &m); for(int i = 1; i <= n-1; ++i) { int x, y; scanf("%d%d", &x, &y); add(x, y); add(y, x); } for(int i = 1; i <= n; ++i) lg[i] = lg[i-1] + (1 << lg[i-1] == i); dfs(s, 0); for(int i = 1; i <= m; ++i) { int x, y; scanf("%d%d",&x, &y); printf("%d\n", LCA(x, y)); } return 0; }
信息
- ID
- 121
- 时间
- 2000ms
- 内存
- 256MiB
- 难度
- 6
- 标签
- 递交数
- 667
- 已通过
- 194
- 上传者